4m^2+7m-9=0

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Solution for 4m^2+7m-9=0 equation: 



4m^2+7m-9=0

a = 4; b = 7; c = -9;
Δ = b2-4ac
Δ = 72-4·4·(-9)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{193}}{2*4}=\frac{-7-\sqrt{193}}{8}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{193}}{2*4}=\frac{-7+\sqrt{193}}{8}
$

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